Ask question

Ask question

All categories

3 years ago

10

Help me please, I have no idea how to do Scale Copies!

2 answers:

lana66690 [7]3 years ago

8 0

I think 15 jdjenskdij

Y_Kistochka [10]3 years ago

4 0

Answer: Count

Step-by-step explanation: You should multiply and use a calculator.

You might be interested in

Please help me. I'm confused.

Sholpan [36]

Answer:

u is 4 and v is 18

7 0

4 years ago

Read 2 more answers

Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).

sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

$(p^4-q^4)(p^4+q^4)$ $\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}$

Therefore, the expression can be simplified as;

$p^8-q^8$

Alternatively, using the theorem of difference of two squares, which is

$a^2-b^2=(a-b)(a+b)$

Hence,

$p^8-q^8=(p^4)^2-(q^4)^2$

7 0

1 year ago

Please help I need help with this question

denpristay [2]

Answer:

2.5% and 2.5 · 10^-3, 0.25, 2/5, √5

Step-by-step explanation:

0.25, 2/5, 2.5 · 10^-3, 2.5%, √5

Now let's list them all in the same form, why not decimals.

0.25 = 0.25

2/5 = 4/10 = 40/100 = 0.4

2.5 · 10^-3 = 2.5 · 0.01 = 0.025

2.5% = 0.025

√5 ≅ 2.236

5 0

3 years ago

HELP DUE IN 15 MINS!

enot [183]

Answer:

m∠1 = 25° (opposite angles are congruent)

m∠2 = 87° ⇒ 180 - (25 + 68)

m∠3 = 68° ⇒ 180 - (87 + 25)

Hope this helps!

3 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago