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kherson [118]
3 years ago
13

What is 5 times 5root5

Mathematics
2 answers:
horsena [70]3 years ago
7 0
That is equivalent to:

I am thinking that you meant:

5*\sqrt[5]{5}  

If so:

5^1*5^(\frac{1}{5}) \,  rule a^b*a^c=a^(b+c)

5^(1+\frac{1}{5})

5^(\frac{6}{5})

6.899

(to nearest one-thousandth)


AleksandrR [38]3 years ago
3 0
<span>55.9016994375 would be your answer</span>
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13

Step-by-step explanation:

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Find the equation of the line that has slope of 7 and passes through the point (-9,2).
lawyer [7]

Answer:

y=7x+65

Step-by-step explanation:

You want to find the equation for a line that passes through the point (-9,2) and has a slope of 7.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 7. So you can right away fill in the equation for a line somewhat to read:

y=7x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-9,2). When x of the line is -9, y of the line must be 2.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 7 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-9,2).

So, why not plug in for x the number -9 and for y the number 2? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-9,2). y=mx+b or 2=7 × -9+b, or solving for b: b=2-(7)(-9). b=65.

The equation of the line that passes through the point (-9,2) with a slope of 7

is

y=7x+65

Have a nice day!

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3 years ago
The product of two numbers is 75
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