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Trava [24]
3 years ago
7

Help please! tyssssm!

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

B. Negative

⁄(⁄ ⁄•⁄ω⁄•⁄ ⁄)⁄

tiny-mole [99]3 years ago
5 0

Answer:

<h2>negative</h2>

Step-by-step explanation:

.................

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Please help me, I don't know how to do this...
Lunna [17]

Answer:

  A.  5

Step-by-step explanation:

The triangle will be a right triangle when the side lengths satisfy the Pythagorean theorem: the sum of the squares of the legs is equal to the square of the hypotenuse.

  (x +1)^2 +x^2 = (√61)^2

  x^2 +2x +1 +x^2 = 61 . . . eliminate parentheses

  2x^2 +2x = 60 . . . . . . .subtract 1, collect terms

  x^2 +x -30 = 0 . . . . . divide by 2, subtract 30

  (x +6)(x -5) = 0 . . . . factor the quadratic

  x = -6 or +5

The solution is x = 5.

_____

Side lengths cannot be negative. Solution values are values of x that make the factors zero. x+6=0 when x=-6, for example.

8 0
2 years ago
Please help I want summer school done. Which graph corresponds to the given function?
Alexus [3.1K]

Answer:

The first option in the first picture

Step-by-step explanation:

Good luck with summer school bud :)

3 0
2 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)
Nitella [24]

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

 

So what we have to do is to look for the values of the variables:

<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>

<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>

 

<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>

<span>b^2 =  49 – 9</span>

<span>b^2  = 40

</span>

Therefore the equation of the hyperbola is:

<span>(x^2 / 9) – (y^2 / 40) = 1</span>

5 0
3 years ago
Read 2 more answers
Help me plz :3 :) :x :P
Sonbull [250]
Yes, she is correct
1/2 + 1/2 = 1 or 0.5 + 0.5 = 1 so half of a wall plus half of a wall equals one hole wall.

That's as simple as I can put it mathematical reasoning. I hope this helps
7 0
3 years ago
How to do this problem
Vera_Pavlovna [14]
X(x-1)(x^2+4)=(x^2-x)(x^2+4)=(x^4)+(4x^2)-(x^3)-(4x)=(x^4)-x(x^2+4)+(4x^2)
6 0
3 years ago
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