Question

What is the solution for the following equation? x^2-6x+9=11

Answer 1

Make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation

if you hahve
ax^2+bx+c=0
x=$\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

1x^2-6x-2=0
a=1
b=-6
c=-2

x=$\frac{-(-6)+/- \sqrt{(-6)^{2}-4(1)(-2)} }{2(1)}$
x=$\frac{6+/- \sqrt{36+8} }{2}$
x=$\frac{6+/- \sqrt{44} }{2}$
x=$\frac{6+/- 2\sqrt{11} }{2}$
x=$3+/- \sqrt{11}$
x=$3+ \sqrt{11}$ or $3- \sqrt{11}$

aprox
x=6.31662 or -0.316625