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Ganezh [65]
3 years ago
8

Decrease 620 by 10%

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

 682

Step-by-step explanation:

620, percentage decreased by - 10% (percent) of its value = 682

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Step-by-step explanation:

10d-3d

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96.3 kg = blank g <br><br> A. 9,360<br> B. 0.0963<br> C. 9.63<br> D. 96,300
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2 years ago
5 grams of chucknorrisidium created, decays at a half-life of 16,000,000 Need 1 gram for experiments. How long before the is 1 g
devlian [24]

Answer:

the time taken for the element to remain 1 gram is 38,400,000 unit.

Step-by-step explanation:

Given;

initial mass, m = 5 g

half life, t = 16,000,000 unit

The time taken for the element to remain 1 gram is calculated as;

          mass remaining                                      time

             5 g                                                        0

             2.5 g                                                    16,000,000

             1.25 g                                                   32,000,000

            0.625 g                                                 48,000,000

Interpolate to obtain the time at 1 gram;

1.25 g ----------------------------------   32,000,000

1 g --------------------------------------------- x

0.625 g --------------------------------------- 48,000,000

\frac{1.25 - 1}{1.25 - 0.625} = \frac{32,000,000 - x}{32,000,000 - 48,000,000} \\\\\frac{0.25}{0.625} = \frac{32,000,000 - x}{-16,000,000} \\\\-4,000,000= 20,000,000 - 0.625x\\\\0.625x = 20,000,000 + 4,000,000\\\\0.625x =  24,000,000\\\\x = \frac{24,000,000}{0.625} \\\\x = 38,400,000

Therefore, the time taken for the element to remain 1 gram is 38,400,000 unit.

         

8 0
2 years ago
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