Line perpendicular to a given line is = 1/m
To find m, use m =y2-y1/x2-x1 formula
m = (8-(-3))/(-7-4)
m = 11/-11,
m = -1
Use y= mx+c to find equation of line
Plug in a pair of values,
-3= -1(4)+ c
c= 1
Thus, equation is:
y = -x+1
Equation of line perpendicular to this line is:
y= x+1
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Answer:
the linearization is y = 1/4x +5/4
the linearization will produce <em>overestimates</em>
the values computed from this linearization are ...
f(3.98) ≈ 2.245
f(4.05) ≈ 2.2625
Step-by-step explanation:
Apparently, you have ...

from which you have correctly determined that ...

so that f(3) = 2 and f'(3) = 1/4. Putting these values into the point-slope form of the equation of a line, we get the linearization ...
g(x) = (1/4)(x -3) +2
g(x) = (1/4)x +5/4
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The values from this linearization will be overestimates, as the curve f(x) is concave downward everywhere. The tangent (linearization) is necessarily above the curve everywhere.
__
At the given values, we find ...
g(3.98) = 2.245
g(4.05) = 2.2625
Answer:
the first one is 14xy+3x-y
the second one nothing can be done so that would be ur answer
the third one nothing can be done so that would be ur answer
the fourth one and the fifth one nothing can be done so that would be ur answer
Answer:
Since both terms are perfect squares, factor using the difference of squares formula,
a2−b2=(a+b)(a−b) where a=x and b=16.(+)x16)
Step-by-step explanation: