The cardinality of the union between two sets is given by
In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are
This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are
elements which are in neither A nor B
Answer:
9 and 7/11
Step-by-step explanation:
i hope this helps
Answer:
1 and 31
Step-by-step explanation:
They both divide by it's self to get the same number.
Answer: 21/4 or 5 1/4
Step-by-step explanation: sorry for the 21/4 if this is wroNG IM SOOO SORRy if it is..
Answer:
The value of P(A and B) is 1/10
Step-by-step explanation:
In case of independent events, the probability of one event doesn't depend on the probability of other events.
Therefore, for an independent events
P(A and B) = P(A) × P(B)
P(A and B) = 2/5 × 1/4
P(A and B) =2/20
P(A and B) =1/10
Therefore, the value of P(A and B) is 1/10
