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schepotkina [342]
2 years ago
12

What is the surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft? Drag and drop the co

rrect answer into the box. 373.25311.04259.243.2
Mathematics
1 answer:
AlekseyPX2 years ago
8 0
 surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft, can be solved by solving the area of each face of a cube. since the cube has 6 faces and all the faces are congruent because it all has the same edge.
so the formulaA = 6s^2where s is the edge lengthA = 6 ( 7.2^2)A = 311.04 sq ft.
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Answer:

Although she's only in middle school, Tameka loves to drive go-carts! Her favorite place to drive go-carts, Drivers Delight, has 3 circular tracks. Track 1 has a radius of 60 feet. Track 2 has a radius of 85 feet. Track 3 has a radius of 110 feet.

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Step-by-step explanation:

6 0
2 years ago
I need help simplifying both of these. thank you!
4vir4ik [10]
<h3>Answer:</h3>
  1. -100x +100; 3
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<h3>Step-by-step explanation:</h3>

The distributive property is your friend. It tells you ...

  a(b + c) = ab + ac

It can also be used to simplify the product of binomials (or other polynomials).

  (a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2

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2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81

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5 0
3 years ago
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fomenos

Answer:

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Step-by-step explanation:

1. If F(x)=5x-6, then you can find the inverse F^{-1}(x):

y=5x-6,\\ \\5x=y+6,\\ \\x=\dfrac{y+6}{5},\\ \\F^{-1}(x)=\dfrac{x+6}{5}.

2. If G(x)=x-4, then

y=x-4,\\ \\x=y+4,\\ \\G^{-1}(x)=x+4.

3. Hence,

G^{-1}(F^{-1}(x))=G^{-1}\left(\dfrac{x+6}{5}\right)=\dfrac{x+6}{5}+4=\dfrac{x+26}{5}.

7 0
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Answer:

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