Well if your finding the slope and y intercept
Slope is -4
Y-int is (0,9)
So you would make the. -4 into -4/1 the you would plot (0,9) on the graph first then on the Y line go down 4 and move to the right 1
( I’m not sure if this helps)
Answer: Yes, radicals can be rationals.
Step-by-step explanation:
Yes, a radical can be rational.
If a square root is a perfect square, you will obtain an integer, and by definition, the integer are rationals (they can be written as simple fractions).
Example:

If the radical has a root <em>n </em>and number inside of the root can be written as a power with exponent
, then you will obtain a radical.
Example:
![\sqrt[3]{64}=\sqrt[3]{4^{3}}=4=\frac{4}{1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5E%7B3%7D%7D%3D4%3D%5Cfrac%7B4%7D%7B1%7D)
A) Y1-Y2/X1-X2
9-4/8-(-2) = 5/10= 1/2
b) 1/2x+b=y <-- plug in a point
1/2(-2)+b=4 <--plugged in (-2,4)
-1+b=4 <-- simplify/solve
b=5
c) 1/2x+5=y
Answer:
C. y=-6
Step-by-step explanation:
The line shown is a horizontal line through the y-axis and has the equation y=4. A parallel line to it is a line that does not cross it. It will also have the form y=a where a is the y-coordinate of its points. The point (-4,-6) is on the line so y=-6 is the line.