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const2013 [10]
3 years ago
5

What is the difference? Write the difference. 8-2=6

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0
In 8-2=6, 6 is the difference.
guajiro [1.7K]3 years ago
7 0
The difference is 6 because it is what we get when we subtract 8 and 2.

Final answer: 6
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Step-by-step explanation:

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What percent is of 80 is 15?​
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The answer is 18.75

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Help pls, math due tonight :(
Olenka [21]

9514 1404 393

Answer:

  • 40 ft
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Step-by-step explanation:

A graphing calculator answers these questions easily.

The ball achieves a maximum height of 40 ft, 1 second after it is thrown.

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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.

  h(t) = -16(t^2 -2t) +24

  h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square

  h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form

Compare this to the vertex form:

  f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'

We see the vertex of our height equation is ...

  (h, k) = (1, 40)

The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.

8 0
3 years ago
A rectangular parcel of land has an area of 6,000 ft2. A diagonal between opposite corners is measured to be 10 ft longer than o
Drupady [299]

Answer:

50ft by 120ft

Step-by-step explanation:

Area of a rectangle = L × W

6000ft² = L × W

L = 6000/W

When a diagonal line divides a rectangle into 2 right angled triangles, the diagonal line = Hypotenuse of either of the triangle and it is the longest side.

The formula for a right angle triangle =

a² + b² = c²( c = hypotenuse)

We are told in the question that:

A diagonal between opposite corners is measured to be 10 ft longer than one side of the parcel

Let us assume the side that the hypotenuse is longer than = Width

Hence, the Diagonal = (W + 10)²

Therefore

L² + W² = (W + 10)²

Since L = 6000/W

W² + (6000/W)² = (W + 10)²

W² + (6000/W)² = (W + 10) (W + 10)

W² + (6000/W)² = W² + 10W + 10W + 100

W² + (6000/W)² = W² + 20W + 100

W² - W² + (6000/W)² = 20W+ 100

6000²/W² = 20W + 100

6000² = W²( 20W + 100)

6000² = 20W³ + 100W²

20W³ + 100W² - 6000² = 0

20W³ + 100W² - 36000000 = 0

20(W³ + 5W² - 1800000) = 0

Factorising the quadratic equation,

20(W − 120)(W² + 125W + 15000) = 0

W - 120 = 0

W = 120

Therefore,

W(Width) = 120feet

Since the Width = 120 feet

We can find the length

6000ft² = L × W

L = 6000/W

L = 6000/120

L = 50 feet

The dimensions of the land, correct to the nearest foot is 50ft by 120ft

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Answer:

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