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ki77a [65]
3 years ago
14

(B^9)^3=b^27 true or false

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0
True........................................
Anna11 [10]3 years ago
4 0
True .......................................
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Josh exercises at the gym 3 3/4 hours a week. He spends 2/5 of his time at the gym lifting weights. How many hours a week does J
Natali5045456 [20]

Answer:

1.5hours

Step-by-step explanation:

Firstly in this question, we convert the time given to minutes.

Using the conversion of 60 seconds make a minute, we have 3/4 hours as 3/4 * 60 = 45 minutes. Let’s add this to a total of 3 hours which is 180 minutes. This gives a total of 225 minutes.

Now, we are told that he spends 2/5 of his time lifting weight. This is equivalent to 2/5 * 225 = 90 minutes

We convert this to hour = 90/60 = 1.5 hours

3 0
3 years ago
SYNTHETIC DIVISION: (2x^4-7x^3+14x^2-55x+21) divided by (2x-7)
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Step-by-step explanation:

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Step-by-step explanation:

sec(x) = 1/cos(x)

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and that is true for the third quadrant.

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Step-by-step explanation:

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We have 4different boxesand 6different objects. We want to distribute the objects into the boxes such that at no box is empty. I
Musya8 [376]

Answer:

Following are the solution to this question:

Step-by-step explanation:

They provide various boxes or various objects.  It also wants objects to be distributed into containers, so no container is empty.  All we select k objects of r to keep no boxes empty, which (r C k) could be done.  All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining (r-k) objects. All can be put in any of k boxes.  Therefore, these (r-k) objects could in the k^{(r-k)} manner are organized.  Consequently, both possible ways to do this are

=\binom{r}{k} \times k! \times k^{r-k}\\\\=\frac{r! \times k^{r-k}}{(r-k)!}

Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one

= \frac{r!k^{r-k}}{(r-k)!}

5 0
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