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Mekhanik [1.2K]
3 years ago
10

Seven and fifty-one thousands

Mathematics
2 answers:
Fofino [41]3 years ago
5 0
Hello there.

Question: <span>Seven and fifty-one thousands

Answer: It can be written as a mixed number:
7 </span>\frac{51}{1000}

Hope This Helps You!
Good Luck Studying ^-^
vaieri [72.5K]3 years ago
4 0
7.0051 as a decimal.
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cliff delivers packages in an office building. he enters through a "skywalk" from there, he goes up 5 floors, down 7 floors, and
mamaluj [8]
You have to kind of go backwards on this one. So, he goes down 10 floors to the first so he’s on the 10th, down 7 floors= 3rd floor up 5 floors= 8th floor
3 0
4 years ago
Can someone please help me do the work
Alla [95]

Answer:

C. 1 and 3

Step-by-step explanation:

You are right, now here's why.

You are looking for two equations that have the same constant of proportionality.  That means they behave the same, that if you enter a X value in one, you'll get the same effect as if you enter it in another.

If you look at all four equations, you'll see that 1 and 3 are essentially the same thing, just that the first one is simplified (4y = 3x) while the other isn't (8y = 6x).  But for each time you enter a X value, the Y value will be 33% (1/3) bigger.

3 0
3 years ago
The proof for the product property of logarithms requires simplifying the expression logb(bx y) to x y. Which property is used t
masya89 [10]

You can use the properties of logarithm to derive the simplified form of the given expression.

The simplification of the given expression requires the given below properties of logarithm

  • log_a(b^c) = c \times log_a(b)\\\\
  • log_b(b) = 1

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

  • b = log_a(c)

Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1

<h3>Using the above properties, to get to the simplified form of the given expression</h3>

The given expression is

log_b(b^{x+y})

Using the property log_a(b^c) = c \times log_a(b)\\\\, we get

log_b(b^{x+y}) = (x+y)\times log_b(b)

Using the property log_b(b) = 1, we get

log_b(b^{x+y}) = (x+y)\times log_b(b) = (x+y) \times 1 = x + y

Thus,

The simplification of the given expression requires the given below properties of logarithm

  • log_a(b^c) = c \times log_a(b)\\\\
  • log_b(b) = 1

Learn more about logarithms here:

brainly.com/question/20835449

3 0
2 years ago
Read 2 more answers
Help please i cant fail this
oksano4ka [1.4K]

Answer:

1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
X=7<br> y=33<br><br> 793x+ 945y= ?
SVETLANKA909090 [29]

Answer:

36736

Step-by-step explanation:

793x+945y=793(7)+945(33)=5551+31185=36736

3 0
3 years ago
Read 2 more answers
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