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Sever21 [200]
4 years ago
15

f 5 + x = 12, and you add -5 to the left side of equation, what should you add to right side of equation?

Mathematics
1 answer:
umka21 [38]4 years ago
7 0

Hi there! :)

<u><em>Answer:</em></u>

<em><u>x=7</u></em>

<em><u>*The answer must have a positive sign.*</u></em>

Step-by-step explanation:

<h2><u><em>Lesson: Addition/Subtraction/Multiplication/and Division property of equality</em></u></h2>

First, you switch sides of an equation.

x+5=12

Then, you subtract by 5 from both sides of an equation.

x+5-5=12-5

You subtract by the numbers from left to right.

12-5=7

<u><em>Final answer is x=7</em></u>

I hope this helps you!

Have a nice day! :)

:D

-Charlie

Thank you! :)

:D

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uranmaximum [27]

Answer:

I hope this makes sense, sorry for the lack of proofs.

Step-by-step explanation:

It is given that S is the midpoint of line QT. The definition of a midpoint is that it bisects the line it is on. So, line QS and line TS are congruent, or the same.

Now, we also know that line QR and line TU are parallel. Because they are parallel, it means that they form congruent corners with lines QS and TS..I think the proof here is "angles opposite to congruent sides are congruent in a triangle." But I'm not sure if this is right. Anyways, this means angles RQS and UTS are congruent.

There's also some proof that when two lines cross, the opposite angles are congruent. This means that angles TSU and QSR are congruent.

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3 0
3 years ago
Forth grade math: What happens to the area of the triangle when one of the dimensions is doubled and halved?
Alja [10]

\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=\stackrel{doubled}{2b} \end{cases}\implies A=\cfrac{1}{2}(2b)(h)\implies \stackrel{\textit{twice as the original area}}{A=bh} \\\\[-0.35em] ~\dotfill

\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=\stackrel{halved}{\frac{h}{2}} \end{cases}\implies A=\cfrac{1}{2}b\left( \cfrac{h}{2} \right)\implies \stackrel{\textit{half of the original area}}{A=\cfrac{1}{2}bh\left( \cfrac{1}{2} \right)}

7 0
4 years ago
Jenette rides her bike to the bus station where she barely makes it in time to catch the bus to work. She spends half an hour on
aleksklad [387]

Answer:

The rate of the bike is approximately 23.14 mph

The rate of the bus is approximately 62.14 mph

Step-by-step explanation:

The given parameters are;

The time Janette spends on her bike to get to bus station = Half an hour = 0.5 hours = 30 minutes

The time Janette spends on the bus on her way to work = Two-thirds of an hour = 2/3 hours

The speed of the bus = 39 mph + The speed with which Janet travels on her bike

The total distance from her home to her work = 40 miles

To answer the question, let the speed with which Janet travels on her bike in miles per hour = x = the rate of the bike

Therefore, we have;

The speed rate of the bus = 39 + x

Distance = Speed × Time

The distance Janet travels to the bus station = The speed with which Janet travels on her bike × The time Janette spends on her bike to get to bus station

The distance Janet travels to the bus station = x × 0.5 = 0.5·x

The distance travelled by the bus from the bus station to her work = The speed of the bus × The time Janette spends on the bus from the bus station to her place of work

∴The distance travelled by the bus from the bus station to her work = (39 + x) × 2/3 hours = 13 + 2/3·x

The total distance from her home to her work = 40 miles = The distance Janet travels to the bus station + The distance travelled by the bus from the bus station to her work

∴ The total distance from her home to her work = 40 miles = 0.5·x + 13 + 2/3·x

Which gives;

40 = 0.5·x + 13 + 2/3·x

40 = 7/6·x + 13

7/6·x = 40 - 13 = 27

7/6·x = 27

x = 27 × 6/7 ≈ 23.14 mph

The rate of the bike = x ≈ 23.14 mph

The rate of the bike ≈ 23.14 mph

The speed rate of the bus = 39 + x ≈ 39 + 23.14  ≈ 62.14 mph

The speed rate of the bus ≈ 62.14 mph.

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Answer:

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Step-by-step explanation:

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C. y= -x + 5

i hope its correct

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