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Sever21 [200]
3 years ago
15

f 5 + x = 12, and you add -5 to the left side of equation, what should you add to right side of equation?

Mathematics
1 answer:
umka21 [38]3 years ago
7 0

Hi there! :)

<u><em>Answer:</em></u>

<em><u>x=7</u></em>

<em><u>*The answer must have a positive sign.*</u></em>

Step-by-step explanation:

<h2><u><em>Lesson: Addition/Subtraction/Multiplication/and Division property of equality</em></u></h2>

First, you switch sides of an equation.

x+5=12

Then, you subtract by 5 from both sides of an equation.

x+5-5=12-5

You subtract by the numbers from left to right.

12-5=7

<u><em>Final answer is x=7</em></u>

I hope this helps you!

Have a nice day! :)

:D

-Charlie

Thank you! :)

:D

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F(t)=t^2-3t<br> g(t)=2t+1<br> find f(g(t))
statuscvo [17]

Answer:

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7 0
2 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
2 years ago
The figures below are rectangles. Which polynomial represents the area of the shaded region? HAVE ALL MY POINTS but answer truth
Aleks04 [339]

Answer:

7x - 1

Step-by-step explanation:

Area of the shaded region = area of the large rectangular - area of the small rectangle

Area of rectangle is given as l*w

Area of the large rectangle = l*w = (x + 5)(x - 1)

Expand

= x(x - 1) +5(x - 1)

= x^2 - x + 5x - 5

Area of large rectangle = x^2 + 4x - 5

Area of small rectangle = l*w = (x + 1)(x - 4)

= x(x - 4) +1(x - 4)

=  x^2 - 4x + x - 4

Area of small rectangle = =  x^2 - 3x - 4

Area of shaded region = (x^2 + 4x - 5) - (x^2 - 3x - 4)

= x^2 + 4x - 5 - x^2 + 3x + 4

Collect like terms

= x^2 - x^2 + 4x + 3x - 5 + 4

= 7x - 1

6 0
3 years ago
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