The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
Given that,
The points A (3, -5) and A' (2, -3).
We have to determine,
The distance between point A and A'.
According to the question,
The distance between two points is determined by using the distance formula.
Then,
The distance between points A (3, -5) and A' (2, -3) is,
Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
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brainly.com/question/8069952
Answer:
$4.50
Step-by-step explanation:
$6.75 divided by 1.5 equals $4.50
The linear equation that is perpendicular to the line x+3y=21 is:
y = 3*x - 6
<h3>How to find the equation of the line?</h3>
A general line in the slope-intercept form is written as:
y = m*x + b
Where m is the slope and b is the y-intercept.
Two linear equations are perpendicular if the product between the two slopes is equal to -1.
Rewriting the given line we can get:
x +3y = 21
3y = 21 - x
y = 21/3 - x/3
y = (-1/3)*x + 21/3
Then the slope is (-1/3), if our line is perpendicular to this one, then:
m*(-1/3) = -1
m = 3
our line is:
y = 3*x + b
To find the value of b, we use the fact that our line passes through (1, - 3)
-3 = 3*1 + b
-3 - 3 = b
-6 = b
The line is y = 3*x - 6
Learn more about linear equations:
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Answer:
6 packages
Step-by-step explanation:
Since the student needs a total of 3/4 pounds of modeling clay we need to calculate how much is 3/4 of 8 since that is the denominator being used to calculate each individual package of clay. Since 3/4 is equal to 0.75 we can simply multiply this by 8 to calculate the total amount of clay needed.
8 * 0.75 = 6
This means that the student will need 6/8 pounds of clay. Since each package brings 1/8 pounds this means that we would need a total of 6 packages in order to have enough clay.
