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choli [55]
1 year ago
5

What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21

Mathematics
1 answer:
docker41 [41]1 year ago
3 0

The linear equation that is perpendicular to the line x+3y=21 is:

y = 3*x - 6

<h3>How to find the equation of the line?</h3>

A general line in the slope-intercept form is written as:

y = m*x + b

Where m is the slope and b is the y-intercept.

Two linear equations are perpendicular if the product between the two slopes is equal to -1.

Rewriting the given line we can get:

x +3y = 21

3y = 21 - x

y = 21/3 - x/3

y = (-1/3)*x + 21/3

Then the slope is (-1/3), if our line is perpendicular to this one, then:

m*(-1/3) = -1

m = 3

our line is:

y = 3*x + b

To find the value of b, we use the fact that our line passes through (1, - 3)

-3 = 3*1 + b

-3 - 3 = b

-6 = b

The line is y = 3*x - 6

Learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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Next, we should subtract 7 from both sides to cancel out the 7 on the right side.
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Finally, we should divide both sides by 2.
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Now let's move on to the next equation.

b) 4(5x-2) = 7(2x+3)
Let's use the distributive property to get rid of the parentheses and their coefficients.
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Now, lets subtract 14x from both sides of the equation.

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Next, let's add 8 to both sides of the equation.

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And divide both sides by the coefficient of x, which is 6.

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Now for the last equation.

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First, we should add 2.5x to both sides to cancel out the -2.5x on the right side of the equation.
4.5x - 6 = 20
Now, let's add 6 to both sides to get the variable term alone.
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