Question

What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21

Answer 1

The linear equation that is perpendicular to the line x+3y=21 is:

y = 3*x - 6

How to find the equation of the line?

A general line in the slope-intercept form is written as:

y = m*x + b

Where m is the slope and b is the y-intercept.

Two linear equations are perpendicular if the product between the two slopes is equal to -1.

Rewriting the given line we can get:

x +3y = 21

3y = 21 - x

y = 21/3 - x/3

y = (-1/3)*x + 21/3

Then the slope is (-1/3), if our line is perpendicular to this one, then:

m*(-1/3) = -1

m = 3

our line is:

y = 3*x + b

To find the value of b, we use the fact that our line passes through (1, - 3)

-3 = 3*1 + b

-3 - 3 = b

-6 = b

The line is y = 3*x - 6

Learn more about linear equations:

brainly.com/question/1884491

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