$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d$

5 0

3 years ago

Tessa bought stock in a restaurant for $173.00. Her stock is now worth $242.20. What is the percentage increase of the value of

frozen [14]

Answer:

The percentage increase in Tessa's stock is 40%

Step-by-step explanation:

Given that:

Previous worth = $173

Worth now = $242.20

We have to find percentage increase which can be known by subtracting previous worth from present worth and multiplying it by 100:

Percentage increase = $242.20 - $173 = $69.2

Percentage increase = $69.2/173 *100

Percentage increase = 40%

i hope it will help you!

7 0

3 years ago