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2 years ago

Change the repeating decimal to a fraction: 0.376376376...

Mathematics

1 answer:

taurus [48]2 years ago

3 0

Answer:

Answer is 3/4

Step-by-step explanation:

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How to find the average<br> of 78, 79, 87, 88, 101, 120, 130

crimeas [40]

Answer:

Add the numbers together and divide by the number of numbers. (The sum of values divided by the number of values).

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3

Mnenie [13.5K]

Answer:

y-y1=m(x-x1)

y-2=1/3(x-3)

y=1/3x+1

3 0

3 years ago

Solve. 2(2z + 5) = 50

Nikitich [7]

Answer:

z = 10

Step-by-step explanation:

Distribute 2 to the terms in the parentheses:

2(2z + 5) = 50

4z + 10 = 50

Subtract 10 from both sides

4z = 40

Divide each side by 4

z = 10

So, the answer is z = 10

5 0

3 years ago

Read 2 more answers

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

___________ is a standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph.

zlopas [31]

Answer:

Unit of measure

Step-by-step explanation:

Unit of measure

When we construct any type of graph the unit of measure needs to be present, becuase the numbers without units are just numbers and with just the numbers we can't have physical interpretation of the situation.

For this reason is importatn to include the units of meausre with the plots since with that we have a point of reference for the variables used.

And satisfy the condition "A standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph."

8 0

3 years ago