<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
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<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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</span><span>Answer: correct choice is B.
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You would have to solve for x the plug in the answer for c into the next equation to find your answer
Answer:
Step-by-step explanation:
perimeter =76 m
L=3+w
w
2L+2W=76
2(3+W)+2W=76
6+2w+2w=76
4w=70
w=70/4
w=17.50
L=17.50+3=20.50
A=L*W=17.50*20.50=358.75m^2
I think it’s 3x
Hope it helps
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