Ask question

Ask question

All categories

4 years ago

12

sharon bought 25 pounds of ground beef and made 100 hamburger patties of equal weight. what is the weight of each hamburger patt

y?

2 answers:

mote1985 [20]4 years ago

7 0

4 pounds. 25 times 4 equals 100.

Aloiza [94]4 years ago

4 0

0.25 grams (25 pounds of beef/100 burgers)

You might be interested in

3x^+5x+2=0 <br> need work shown plz

Alexxandr [17]

Answer:

${3x}^{2} + 5x + 2 \\ = {3x}^{2} + 3x + 2x + 2 \\ = 3x(x + 1) + 2(x + 1) \\ = (3x +2)(x + 1)$

7 0

3 years ago

Read 2 more answers

Sin theta = -5/13 and cos theta = -12/13 use ratio identity to find cot theta

Virty [35]

This is in the 3rd quadrant, so -12 is the adjacent side of the 5,12,13 triangle.
Cot(theta) = -12/(-13) = 12/13

4 0

3 years ago

Plz help i dont understand this at all

NISA [10]

Answer:

(-4,-1)

Step-by-step explanation:

Look at where the lines on the graph intersect, then find the point.

6 0

3 years ago

Read 2 more answers

Please answer this question based on the following data. SSTR = 6,750 H0: μ1= μ2=μ3=μ4 SSE = 8,000 Ha: at least one mean is diff

Nookie1986 [14]

Answer:

$P_v =P(F_{3,16}>4.5)=0.0180$

So on this case the best option for the answer would be:

between .01 and .025

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $4$ groups and on each group from $j=1,\dots,5$ we have $5$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =6750$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8000$

And we have this property

$SST=SS_{between}+SS_{within}=6750+8000=14750$

The degrees of freedom for the numerator on this case is given by $df_{num}=k-1=4-1=3$ where k =4 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=20-4=16$ .

And the total degrees of freedom would be $df=N-1=20 -1 =19$

We can find the $MSR=\frac{6750}{3}=2250$

And $MSE=\frac{8000}{16}=500$

And the we can find the F statistic $F=\frac{MSR}{MSE}=\frac{2250}{500}=4.5$

And with that we can find the p value. On this case the correct answer would be 3 for the numerator and 16 for the denominator.

$P_v =P(F_{3,16}>4.5)=0.0180$

So on this case the best option for the answer would be:

between .01 and .025

6 0

4 years ago

Solving zero product property

ryzh [129]

If is was a property in think it would be Identity Property of Addition

4 0

3 years ago