B 16 miles an hour
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Answer:
2 days
Step-by-step explanation:
Use the given formula
y = 5x + 4
The information:
y is the money spent
x is the number of days
It is known that Justin spent $18
so now just substitute in that value
$18 = 5x + 4
and simplfiy by inverse operations
18 = 5x + 4
-4 -4
14 = 5x
/5 /5
2.8 = x
As per this problem, one can infer that renting a game is done by days, and will be charged in days, hence renting a game for 0.8 days is pointless
meaning that the final answer is 2 full days
The experimental probability is, as the name suggests, a probability based on observation. If we say that the experimental probability of seeing a hawk at the Avian Viewing Center on any given day is 20%, it means that someone has visited the center for many days, and at the end of this experiment he has met hawks on 20% of the days, i.e. one out of five days.
If we assume that these measurement are trustworthy, we can assume that Allison will also see a hawk on one fifth of the days.
Since she will visit the center for 240, she should expect to see a hawk on one fifth of these days, i.e.
days.
The system of inequalities that represents the given situation are x + y ≤ 20 and 15x + 10y ≥ 90.
The parameters needed to model the inequalities;
- amount made by Opal working for a photographer = $15 per hour
- amount made in the soccer team = $10 per hour
- minimum amount Opal needs to make a week = $90
- maximum number of hours Opal needs to work = 20 hours
Let the number of hours Opal works for a photographer = x
Let the number of hours Opal works in soccer team = y
The first system of inequality in the given situation is represented as;
x + y ≤ 20
The second system of inequality in the given situation is represented as;
15x + 10y ≥ 90
Thus, the system of inequalities that represents the given situation are x + y ≤ 20 and 15x + 10y ≥ 90.
learn more here: brainly.com/question/9774970
Answer:
Between the two sides
Step-by-step explanation:
No Man's Land was the land that separated the Allies and Axis powers in both World Wars.
