A figure with 6 faces, 8 vertices, and 12 edges
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
Hello There!
To solve for the area of this figure we need to split the figure into 3 different parts:
A rectangle with a length of 9 ft and a width of 7 ft
a rectangle with a width of 9ft + 7ft and a length of 25 ft
a rectangle with a width of 18 ft and a length of 22 ft
To find the area of a rectangle we use the formula
where w = width and l = length
for the first one we plug in the values
A = 9 * 7
9 * 7 = 63 so the area of the smallest rectangle is 63ft²
Now lets find the area of the larger rectangle
The dimensions are l = 25 ft and w = 9 + 7 (16 ft)
Now we can plug in the values into the area formula
A = 16 * 25
16*25=400 so the area of the larger rectangle is 400 ft²
Now lets find the area of the last rectangle
The dimensions are l = 22 ft and w = 18 ft
now lets plug in the values to the formula
A = 22 * 18 =396
so the area of the last rectangle is 396 ft²
Finally we want to add all of the areas together
396 + 400 + 63 = 859
So the area of the figure is 859 ft²