Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Answer:
x=1
Step-by-step explanation:
you would change it to 5x-4(-3x+5)=-3, because you put the info for the first equation into the second equation.
5x-4(-3x+5)=-3
5x+12x-20=-3
17x-20=-3
17x=17
x=1
The ans should be ASA because angle AVR is equal to angle EVN (opposite angles equal)
Answer:
f'(9) = 6
Step-by-step explanation:
f(x) = 6x+7
The derivative is
f'(x) = 6
Evaluated at x=9
f'(9) = 6
Answer:
k = -5 and i think the other one is k=0
Step-by-step explanation:
