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jasenka [17]
3 years ago
14

The length of a rectangular patio is 14 feet more than its width, 2w. The area of a patio, A(w), can be represented by the funct

ion
Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer: 4w^2 + 28w.

Step-by-step explanation:

Width of the rectangle= 2w

Length if the rectangle= 2w+14

Area of a rectangle= length×width

= 2w(2w+14)

= 4w^2 + 28w

The area of the rectangular patio A(w) is 4w^2 + 28w.

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What is 1.5 m - 5 cm ?
Alenkasestr [34]

Answer:

1.45 m

Step-by-step explanation:

Convert 1.5 metre into cm

1.5 metre =150 center meters

150 cm -5=145

145 into metres is 1.45 m

7 0
3 years ago
Y=-x^2-x-3 find the X intercept for The parabola define by this equation
KengaRu [80]
To find the X intercept make y =0. Then factor out a negative on the side with the equation for each of the terms, so it becomes
0=-(x^2+x+3)
0=(x^2+X+3)
0-3=(x^2+X)
-3=x(X+1)
-3=X, X intercept -3,0
-3=(X+1)
-4=X, X intercept -4,0.
These are possible X intercepts you can check by using quadratic formula as well.
7 0
3 years ago
PLS HELP ME
MrRa [10]


false... even if you got 100 on the next test, you would only have an 84 average


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3 0
3 years ago
Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B
jeka94
\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0

M_y=35x^4+14x^5-6y^2-12xy^2
N_x=35x^4-6y^2

\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2

This suggests an integrating factor depending on x only is possible, and given by

\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}

Distributing across the ODE, we end up with

\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0

The equation is now exact, with

{M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}

Now we find the solution:

F_x=M^*
F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx
F=(7x^5y-2xy^3)e^{2x}+f(y)

F_y=N^*
(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}
f'(y)=0
\implies f(y)=C

The general solution is then

F(x,y)=(7x^5y-2xy^3)e^{2x}=C
7 0
4 years ago
Which expression is equivalent to 2*3 / 2^6<br> A 2^2<br> B 1/2^2<br> C 2^8<br> D 1/2^8
harkovskaia [24]

Answer:

Step-by-step explanation:

B

7 0
3 years ago
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