A circle with the equation (x + 3)2 + (y - 2)2 = 25 is reflected over the line x = 2.

1 answer:

7 0

So the circle has and equation of (x+3)2+(y-2)2=25 and its reflected over the line of two. So first in your problem is to simplify the function which could represent the y=mx+b. So it goes like this:
2x+6+2y-4=25
-2y=-2x-6+25
y=-2x-6+25/-2
y=x-25/2

so it means the answer would be in this kind of formula and i hope you can solve it cause im confused also so here is the formula:
(x-h)2-(y-k)2=25

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Write the area A of a square as a function of its perimeter P. ...?

Svetradugi [14.3K]

The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16

4 0

3 years ago

Please help I need to get this doneeeee

Alex17521 [72]

Jan. = -15

Feb. = +10

Mar. = -5

Apr. = +50

May = -25

June = -20

⭐ Answered by Hyperrspace (Ace) ⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐