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xz_007 [3.2K]
4 years ago
9

What is the value for m for this equation: 3m - 6.8 = 31?

Mathematics
2 answers:
Mars2501 [29]4 years ago
7 0
The answer is B..............
Karo-lina-s [1.5K]4 years ago
6 0
Ok, so you your first move would be isolating 3m, for that you'll have to take 6.8 away from the left side by subtracting it from itself. so It'll be 3m= 6.8+31. 6.8 turns positive because when a number is moved to another side of the equal side, the sign changes. So after this add 31 and 6.8. You'll get 37.8. So teh equation will be 3m-37.8. To find M divide 3 from both sides. 3m/3 is equal to m. and 37.8/3 is equal to 12.6. Hope that helped :D
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At the beginning of a snowstorm, Nathaniel had 5 inches of snow on his lawn.
vivado [14]

Answer:

In 5 hours he would have 7.5 inches of snow JUST from the snowstorm but the question says that he already had 5 inches in his lawn so that would make 12.5 inches of snow in 5 hours.

The second one says t, it doesn't state a number so lets assume the number is ten. So that's 5 more hours of constant snowfall, this makes our total be the sum of 12.5+7.5. This is equal to 20.

10 hours into the snowstorm Nathaniel had 20 inches of snow in his lawn.

Consider a brainliest if it helps :)

3 0
3 years ago
Read 2 more answers
In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
stepan [7]
2 students have both their nose and ears pierced
6 0
3 years ago
Help math question derivative!
atroni [7]
Let f(x)=\sec^{-1}x. Then \sec f(x)=x, and differentiating both sides with respect to x gives

(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1
f'(x)=\dfrac1{\sec f(x)\tan f(x)}

Now, when x=\sqrt2, you get

(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}

You have \sec^{-1}\sqrt2=\dfrac\pi4, so \sec\left(\sec^{-1}\sqrt2\right)=\sqrt2 and \tan\left(\sec^{-1}\sqrt2\right)=1. So (\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}
5 0
4 years ago
Mileage tests are conducted for a particular model of automobile. If a 98% confidence interval with a margin of error of 1 mile
Llana [10]

Answer: 37

Step-by-step explanation:

Given : Significance level : \alpha:1-0.98=0.02

Critical value : z_{\alpha/2}=z_{0.01}=2.33

margin of error : E= 1 mile per gallon

Population standard deviation: \sigma=2.6 miles per gallon.

We know that when the population standard deviation is known then the formula to find the sample size is given by  :

n=(\dfrac{z_{\alpha/2}\times \sigma}{E})^2

n=(\dfrac{(2.33)\times 2.6}{1})^2=36.699364\approx37  [Round to the next whole number.]

Hence, the required number of automobiles should be used in the test = 37

7 0
4 years ago
What is 9 tens more than 99 190​
Oksana_A [137]
99 plus 9 tens?? if so, 189
5 0
3 years ago
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