1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xz_007 [3.2K]
4 years ago
9

What is the value for m for this equation: 3m - 6.8 = 31?

Mathematics
2 answers:
Mars2501 [29]4 years ago
7 0
The answer is B..............
Karo-lina-s [1.5K]4 years ago
6 0
Ok, so you your first move would be isolating 3m, for that you'll have to take 6.8 away from the left side by subtracting it from itself. so It'll be 3m= 6.8+31. 6.8 turns positive because when a number is moved to another side of the equal side, the sign changes. So after this add 31 and 6.8. You'll get 37.8. So teh equation will be 3m-37.8. To find M divide 3 from both sides. 3m/3 is equal to m. and 37.8/3 is equal to 12.6. Hope that helped :D
You might be interested in
Are 9/21 and 6/14 equivalent fractions
sesenic [268]

Answer:

Yes

Step-by-step explanation:

9/21 SIMPLIFIED= 3/7

6/14 SIMPLIFIED= 3/7

5 0
2 years ago
Read 2 more answers
Line l and line k are perpendicular. Line l has a slope of 3. Line k contains the points (5, 8) and (2,
andrezito [222]

Answer:

y = 9

Step-by-step explanation:

Calculate the slope m of line k using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (5, 8) and (x₂, y₂ ) = (2, y)

m = \frac{y-8}{2-5} = \frac{y-8}{-3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m}

The slope of line l is m = 3, thus slope of line k is

m = - \frac{1}{3}

Equating the 2 slopes for line k

\frac{y-8}{-3} = - \frac{1}{3} ( multiply both sides by - 3 )

y - 8 = 1 ( add 8 to both sides )

y = 9

7 0
3 years ago
5 squared - -9 squared / 5 - -9​
allsm [11]

Answer:

25 & 81

Step-by-step explanation:

5 squared is 25

9 squared is 81

if that's what you're looking for

8 0
4 years ago
Read 2 more answers
A psychologist claims that less than 5.8 percent of the population suffers from professional problems due to extreme shyness. Ex
otez555 [7]
In statistics, you may test a hypothesis using different statistical techniques like ANOVA or the F-test. You should have the null hypothesis, denoted as H0 and the alternative hypothesis, denoted as H1. Null hypothesis is the hypothesis you would like to test on. This is called as such because this is the hypothesis statisticians would like to test to nullify. This would be p < 5.8%. On the other hand, the alternative hypothesis is the contrary of the null hypothesis. Hence, the alternative hypothesis is p ≥ 5.8%. The answer is C.
4 0
3 years ago
Read 2 more answers
How much is 90p in Shillings?
Helga [31]
<span>90 Kenyan Shilling equals</span><span><span>0.5687 </span>British Pound</span>
8 0
3 years ago
Other questions:
  • Sec x tan x (1-sin^2 x) = __x I need help solving this I have no idea.
    14·1 answer
  • How do you find the angle??​
    6·1 answer
  • If x=6 is the only X-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the
    9·1 answer
  • {(1/sqrt(2))^n} from n=1 to infinity; is the series convergent or divergent? if convergent, why? and sum?
    6·1 answer
  • A suit is on sale for $154. If the original price of the suit was $440, what percent was discounted for the sale? A. 65% B. 25%
    13·1 answer
  • Please help?? Thank you very much in advance
    15·2 answers
  • I really need the help please and thank you
    13·1 answer
  • PLEASE HELP Which parametric equations represent y = – |x|? Check all that apply.
    8·1 answer
  • Please help ASAP. I need someone to check my Geometry answer and explain why I am right or wrong. REAL ANSWERS ONLY. 20 PTS!
    9·1 answer
  • There are 8 kids at a birthday party. If there are 6 girls and 2 boys at a party what fraction of the kids are girls?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!