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Valentin [98]
4 years ago
15

PLZ HELP WILL GIVE BRAINLIEST + 10 POINTS

Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
6 0

Answer:

4/3

Step-by-step explanation:

4^-3*3^4*4^2=20.25

3^5*4^-2=15.1875

20.25/15.1875=4/3 in lowest terms

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What is the measure of arc CD?
CaHeK987 [17]

Option C:

The measure of arc CD is 40°.

Solution:

Given data:

m∠X = 11° and m(arc AB) = 18°

To find the measure of arc CD:

We know that,

<em>Angle formed by two intersecting secants outside the circle is equal to half of the difference between the intercepted arcs.</em>

$m \angle X =\frac{1}{2}({arc  \ CD}-{arc}  \ AB)

$ 11^\circ =\frac{1}{2}({arc}  \ CD-{18^\circ})

Multiply by 2 on both sides.

22° = arc CD - 18°

Add 18° from both sides.

40° = arc CD

Switch the sides.

arc CD = 40°

Hence the measure of arc CD is 40°.

Option B is the correct answer.

7 0
3 years ago
Whats the area of x=9 ft, x=22ft, and z=109*
jekas [21]
The answer is 361 to the third power
8 0
3 years ago
What is the probability of choosing a diamond card out a regular deck of 52?
bazaltina [42]
There are 13 diamonds in a regular deck of cards.

So the probability of picking a diamond card is 13/52.
3 0
4 years ago
Read 2 more answers
Can someone help me find the answer to these 3 problems if so thank you .
alexandr1967 [171]

Answer:

1. r+s²=49

2. pq²=24

3. -4xy-6x²+2x²y-6y= -54

Step-by-step explanation:

1. r+s²=0+7²=49

2. pq²=(6)(2)²=6(4)=24

3. -4xy-6x²+2x²y-6y= -4(3)(2)-6(3)²+2(3)²(2)-6(2)

                                = -24-6(9)+2(9)(2)-12

                                = -24-54+36-12

                                = -78+36-12

                                = -42-12

                                = -54

5 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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