Answer:
(A) 2/3 [√(4-4x)]^3
(B) 2/3 [√(4-x)]^3
Step-by-step explanation:
Integrating the functions,
(A) Any function in square root is equal to or same as the function raised to the power of 1/2
To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2
Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.
Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.
Here, the denominator is 2, so you take the square root of the function, and raise the function to the power of 3
So the integral of Y = √[4-4x] is
2/3 [√(4-4x)]^3
(B) In like manner, the integral of
Y = √[4-x] is
2/3 [(√4-x)]^3
Answer:
$10.17
Step-by-step explanation:
9 x .13 = 1.17
9 + 1.17 = 10.17
Answer:
x -2y = -4
Step-by-step explanation:
The slope of the line between points C and D is ...
m = (y2 -y1)/(x2 -x1)
m = (7 -13)/(5 -2) = -6/3 = -2
The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...
y -k = m(x -h) . . . . line with slope m through point (h, k)
y -1 = 1/2(x -(-2))
We can rearrange this to standard form.
2y -2 = x +2 . . . . . multiply by 2
-4 = x -2y . . . . . . . subtract 2y+2
x -2y = -4 . . . . . . standard form equation of the desired line
change into improper fraction then do the problem then turn back into mixed number
