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Aleks [24]
3 years ago
11

Due to fire laws no more than 720 people may attend a performance at metro auditorium. the balcony holds 120 people. there are 3

2 rows on the ground floor, each with the same number of seats. write an inequality to find the numbers of people that can sit in a ground floor row if the balcony is full. indentify what your variable represents WRITE ME A INEQUALITY AND WHAT THE VARIABLE REPRESENTS
Mathematics
2 answers:
jolli1 [7]3 years ago
5 0
32*x < 720-120 
32*x < 600
x < 18.75

because of x represents the number of seats in each row, it has to be a natural number -- whole. so x=18 is the max number of seats in each row and x < 18.75 is the desired inequality. 
snow_lady [41]3 years ago
3 0

Answer: x\leq 18.75 is the inequality and x is the number of seats in each row in the ground floor.

Step-by-step explanation:

Since, The total number of people may attend = People in the balcony + People in the ground floor.

And, According to the question, Number of the people in the balcony = 120

Now, Let x represents the number of the seats in the ground floor,

While y represents total number of people.

And, again according to the question,

There are 32 rows on the ground floor,

Therefore, the number of the people in the ground floor = 32 x

y = 120 + 32 x

But, the total number of the people must be not more than 720.

Therefore, y \leq 720

⇒ 120 + 32 x\leq 720

⇒  32 x\leq 720-120

⇒ x\leq 18.75

Where x is the number of seats in the ground floor.

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Answer:

11

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Step-by-step explanation:

3 0
3 years ago
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Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

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P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

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6 0
3 years ago
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti
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Answer:

1 3/7 quarts should be drained off and replaced with pure antifreeze.

1 3/7 ≈ 1.4286

Current amount of antifreeze in quarts is -

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Let the amount drained of and replaced with antifreeze be x-

The amount left after draining off is 10 − x.

The amount of antifreeze  is 30/ 100 (10−x).

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10- 1 3/7 = 8 4/7

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