Two sides of a right triangle are equal to 3m and 4m. Find the length of the third side. (Two cases)
2 answers:
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2+20t-5t^2=12
5t^2-20t+10=0
t^2-4t+2=0 complete the square
t^2-4t=-2
t^2-4t+4=2
(t-2)^2=2
t-2=±
t=2±
t≈(0.586, 3.41)
5t^2-20t+10=0
t^2-4t+2=0 complete the square
t^2-4t=-2
t^2-4t+4=2
(t-2)^2=2
t-2=±
t=2±
t≈(0.586, 3.41)