Answer:
0J
Explanation:
Mass of the lump M1 = 1.0 kg, initial velocity of the lump U1 = 2m/s to the right,
mass of the metal sphere M2 = 0.5kg, initial velocity of the metal sphere M2 = -4m/s to the left. using conservation law of momentum;
M1U1 + M2U2 = V (M1 + M2)
(1.0 × 2) + (0.5 × -4) = V (1 + 0.5)
2 -2 = V (1.5)
0 = V (1.5)
divide both side by 1.5
0/1.5 = V 1.5/1.5
V = 0
since final velocity after sticking together of the two masses equals zero then their combined kinetic energy will also equal to zero
1/2 V(M1 +M2)
1/2 ×0 × 1.5 = 0J
Answer: −2x2+x−10
Explanation:
x2−x−3−1−3x2+2x−6
= x2+−x+−3+−1+−3x2+2x+−6
Combine Like Terms:
= x2+−x+−3+−1+−3x2+2x+−6
= (x2+−3x2)+(−x+2x)+(−3+−1+−6)
= −2x2+x+−10
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