The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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14, 28 I think:) sorry if not
Answer:
<h2><u>
X= 1</u></h2>
Step-by-step explanation:
<em>y = 5 - 3x</em>
<em>5x - 4y = -3</em>
you substitute for y since you know what y equals.
so, it will then be
5x -4(5 -3x) = -3
you then multiply -4 by everything in the parenthesis
so then it will be
5x - 20 + 12x = -3
Then combine like terms
5x + 12x = 17x
then the new equation is
17x -20 = -3
the next step is to and 20 to both sides since it is negative you do the opposite.
17x - 20 = -3
<u> + 20 +20</u>
17x = 17 divide 17 by both sides sice 17 is being multiplied by x you do the opposite and divide and you get 1.
<h2><u>
so, X = 1</u></h2>
log(3x) = log(2x-4)
taking antilog of both sides:
3x = 2x - 4
3x - 2x = -4 [subtracting 2x from both sides]
x = -4
and we're done already!
Answer:
<h2>(6 3/5) * (x)</h2>
Step-by-step explanation:
3x(2 1/5)= (6 3/5) * (x)
