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jenyasd209 [6]
3 years ago
8

What are the domain and range of this function

Mathematics
1 answer:
belka [17]3 years ago
3 0
f(x)=\sqrt{x-7}+9\\\\\text{the domain:}\\x-7\geq0\to x\geq7\\\\\text{the range:}\\\sqrt{x-7}\geq0\ \text{therefore}\ \sqrt{x-7}+9\geq9\\\\y\geq9

Answer:\\domain:\ x\geq7\\range:\ y\geq9
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- 1/2 (-3/2x + 6x +1) -3
Tcecarenko [31]
-1/2(-3/2x + 6x + 1) - 3

Simplify.

(3/4x - 3x - 1/2) - 3

Get rid of the parenthesis.

3/4x - 3x - 1/2 - 3

Add like terms.

(3/4x - 3x) + (-1/2 - 3)

Simplify.

-2 1/4x + (-3 1/2)

Get rid of the parenthesis.

-2 1/4x - 3 1/2

Hope I helped! :)

4 0
3 years ago
I need help solving this please
kotykmax [81]
I believe the answer would be 9
7 0
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Sindrei [870]
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4 0
2 years ago
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Lerok [7]

Step-by-step explanation:

First, replace f(x) with y ⇒ f(x)=6x-19 ⇒ y=6x-19

Then y with x and x with y  ⇒ y=6x-19 ⇒ x=6y-19

Solve the equation from for y:

           x=6y-19

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Replace y with f−1(x) ⇒ f−1(x)= 1/6 x +(19/6)

hope this helps!

           

5 0
3 years ago
Whats the sum of the interior angles of a 37 gon
Zinaida [17]
Since we have a 37-gon here, the sum of the interior angles will be: 
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