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jenyasd209 [6]
3 years ago
8

What are the domain and range of this function

Mathematics
1 answer:
belka [17]3 years ago
3 0
f(x)=\sqrt{x-7}+9\\\\\text{the domain:}\\x-7\geq0\to x\geq7\\\\\text{the range:}\\\sqrt{x-7}\geq0\ \text{therefore}\ \sqrt{x-7}+9\geq9\\\\y\geq9

Answer:\\domain:\ x\geq7\\range:\ y\geq9
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Meg found one treasure at − 3 4 foot. Which of these location are higher than − 3 4 foot? Check all that apply. Negative StartFr
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Answer:

\frac{-1}{4}and \frac{-5}{8} are the locations higher than \frac{-3}{4} foot

Step-by-step explanation:

We are given that Meg found one treasure at \frac{-3}{4}foot

We are supposed to find Which of these location are higher than \frac{-3}{4}foot?

i) -\frac{7}{8}

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ii)-\frac{1}{4}

So, -\frac{1}{4}>\frac{-3}{4}

So, this location is higher than\frac{-3}{4} foot

iii) - 1 foot

-1 < \frac{-3}{4}

So,this location is not  higher than\frac{-3}{4}foot

iv)-2 feet

So,this location is not  higher than\frac{-3}{4}foot

v)\frac{-5}{8}

So, this location is higher than \frac{-3}{4}foot

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