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Aleonysh [2.5K]
3 years ago
8

What is the decimal of 64/100

Mathematics
2 answers:
Anarel [89]3 years ago
7 0
Move the decimal point twice to the left


64.0

0.64
DENIUS [597]3 years ago
6 0

Answer:

0.64

Step-by-step explanation:

Divide the numerator by the denominator. hope this helps! :))

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WILL MARK BRAINLIEST!! The coordinates of the vertices of quadrilateral JKLM are J(-3,2), K(4,-1), L(2,-5) and M(-5,-2). Find th
irinina [24]
Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
5 0
3 years ago
Using the functions f(x) = (3 - x)/(x2 + 4) and g(x) = 3x, find the value of (f*g)(2).
wariber [46]

9514 1404 393

Answer:

  (f×g)(2) = 3/4

Step-by-step explanation:

For each of the functions, put 2 where x is and evaluate the expression.

  f(2) = (3 -2)/(2² +4) = 1/8

  g(2) = 3×2 = 6

Then the product is ...

  (f×g)(2) = f(2)×g(2) = (1/8)×6 = 6/8

  (f×g)(2) = 3/4

4 0
2 years ago
Can someone help me
barxatty [35]

Answer:

y= (-6/5)x -2

Step-by-step explanation:

y=mx+b , where m is the slope, and b is the y -intercept

the y -intercept is where the line intersects the y-axis so b = -2

the slope m= y(rise) /x(run)  = 6/-5 = -6/5 ( to find the slope you have to know how to get from any point on the line to another point on the same line; start at point (0,-2) go up 6(y-rise) and to the left 5(x-run) at point (-5,4))

y= (-6/5)x -2

4 0
2 years ago
From the set (33, 15, 12), use substitution to determine which value of x makes the equation true.
zepelin [54]
X=12 because 3 times 12 equals 36. if you divide by 3 on both sides you would be left with that
8 0
3 years ago
If AB=2(x+1) BC=3x+1 and AC=4(x+2) then find the value for x,AB,BC and AC
taurus [48]

Givens

AB + BC = AC

AB = 2(x + 1)

BC = 3x + 1

AC = 4(x + 2)

Substitute and Solve

AB + BC = AC

2(x + 1) + 3x + 1 = 4(x + 2)     Remove the brackets on the left

2x + 2 + 3x + 1 = 4(x + 2)      Collect the like terms on the left

5x + 3  = 4(x + 2)                  Remove the brackets on the right.

5x + 3 = 4x + 8                     Subtract 4x from both sides.

5x - 4x + 3 = 8            

x + 3 = 8                               Subtract 3 from both sides

x =8 - 3

x = 5

Answers

AB=2(5 + 1) = 2 * 6 = 12

BC = 3x + 1 = 3*5 + 1 = 15 + 1 = 16

AC = 4(5 + 2) = 4*7 = 28


7 0
3 years ago
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