Answer:
OH−(aq), and H+(aq)
Explanation:
Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;
MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)
The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.
For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.
Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.
Answer:
68.1% is percent yield of the reaction
Explanation:
The reaction of methane with oxygen is:
CH₄ + 2O₂ → CO₂ + 2H₂O
<em>Where 2 moles of oxygen react per mole of CH₄</em>
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Percent yield is:
Actual yield (28.2g CO₂) / Theoretical yield * 100
To solve this question we need to find theoretical yield finding limiting reactant :
<em>Moles CH₄:</em>
15.1g CH₄ * (1mol / 16.04g) = 0.9414 moles
<em>Moles O₂:</em>
81.2g * (1mol / 32g) = 2.54 moles
For a complete reaction of 0.9414 moles of CH₄ are needed:
0.9414 moles CH₄ * (2 mol O₂ / 1mol CH₄) = 1.88 moles of O₂. As there are 2.54 moles, O₂ is in excess and <em>CH₄ is limiting reactant</em>
In theoretical yield, the moles of methane added = Moles of CO₂ produced. That is 0.9414 moles CO₂. In grams = Theoretical yield:
0.9414 moles CO₂ * (44.01g / mol) = 41.43g CO₂
Percent yield: 28.2g CO₂ / 41.43g CO₂ * 100=
<h3>68.1% is percent yield of the reaction</h3>
Answer:
Solution
dT = K * b
K (H2O) = 1.86 0C
b(C2H6O2) = dT/ K = 33.2 / 1.86 = 17.85(mol/kg)
b(C2H6O2)= n (C2H6O2) / m (H2O)
m (H2O) = V * = 12.2 * 1 = 12.2 (kg)
n (C2H6O2) = b (C2H6O2) * m (H2O) = 17.85 * 12.2 = 217.77 (mol)
n (C2H6O2) = m / M;
m (C2H6O2) = n * M = 217.77 * (12*2 + 1*6 + 16 *2) = 13501.74 (g) = 13.5 (kg)
V (C2H6O2) = m / = 13.5 / 1.11 = 12.16 (L)
Answer V (C2H6O2) = 12.16 L
For the reaction c2h6 (g) → c2h4 (g) + h2 (g) δh° is 137 kj/mol and δs° is 120 j/k ∙ mol. the reaction is spontaneous at high temperatures. the correct answer is option(b).
A spontaneous reaction is one that favors the creation of products in the environment in which it is taking place. A campfire that is roaring is an exothermic example of a spontaneous reaction (there is a decrease in the energy of the system as energy is released to the surroundings as heat).
There are some reactions that are only spontaneous at very high temperatures according to the Gibbs Free Energy equation. The reaction is spontaneous at high temperatures if both S, or entropy, and H, or enthalpy, are positive. We want the Gibbs free energy to be negative according to the formula G = H - T - S.
The complete question is:
For the reaction
C2H6 (g) → C2H4 (g) + H2 (g)
ΔH° is +137 kJ/mol and ΔS° is +120 J/K ∙ mol. This reaction is ________.
A) spontaneous at all temperatures
B) spontaneous only at high temperature
C) spontaneous only at low temperature
D) nonspontaneous at all temperatures
To know more about spontaneous reaction refer to: brainly.com/question/1217654
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