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shepuryov [24]
3 years ago
9

In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidat

ion equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction method or the oxidation number method. The half-reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(l), OH−(aq), and H+(aq) may be added to complete the mass balance. Which substances are used depends on the reaction conditions.
Chemistry
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

OH−(aq), and H+(aq)

Explanation:

Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;

MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)

The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.

For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.

Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.

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How many grams of calcium chloride would you need to make 1 L of solution containing 5 ppm calcium (Ca)?
Tresset [83]

Explanation:

The given data is as follows.

           Volume = 1 L,    Concentration of Ca = 5 ppm or 5 mg/L

As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.

Hence, calculate molarity of calcium as follows.

           Molarity of Ca = \frac{\text{given concentration}}{\text{molar mass}}

                                  = \frac{0.005 g/l}{40.078 g/mol}

         Molarity of Ca = 1.25 \times 10^{-4} M

Hence, molarity of CaCl_{2} is 1.25 \times 10^{-4} M. Since, volume is same so, moles of calcium chloride will be 1.25 \times 10^{-4} mol.

Thus, we can conclude that mass of CaCl_{2} will be as follows.

             1.25 \times 10^{-4} \times 110.984       (molar mass of CaCl_{2} = 110.984 g/mol)

               = 0.0138 g

Thus, we can conclude that mass of CaCl_{2} is 0.0138 g.

4 0
3 years ago
How many moles does 21. 7 L of gas at STP represent?
Oduvanchick [21]

Answer:

.96875 moles

Explanation:

22.4 liters per mole at STP for a gas

21.7 / 22.4 = .96875 moles

3 0
2 years ago
If I have 5.00g of solid CO₂ that is allowed to sublimate (turn to gas) in an empty balloon. How many moles of CO₂ are present i
r-ruslan [8.4K]

56g is the coreect acsnw

8 0
2 years ago
A student was comparing the solubility of equal amounts of table salt and table sugar at different temperatures.The table below
alexgriva [62]
First, we distinguish whether table sugar or table salt will be more soluble. The bonds between the molecules of the table sugar are weaker than the bonds between the molecules of salt. Therefore, it is easier for the sugar molecules to dissolve.
Next, we evaluate the effect of temperature on solubility. As the temperature of a solvent increases, it is able to hold more and more solute. This means that the sample with table sugar kept at the highest temperature will contain the most dissolved solute, and this is sample 1.
5 0
3 years ago
Read 2 more answers
When the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solu
gtnhenbr [62]

Answer:

The unknown solution had the higher concentration.

Explanation:

When two solutions are separated by a semi-permeable membrane, depending on the concentration gradient between the two solutions, there is a tendency for water molecules to move across the semi-permeable in order to establish an equilibrium concentration between the two solutions. This movement of water molecules across a semi-permeable membrane in response to a concentration gradient is known as osmosis. In osmosis, water molecules moves from a region of lower solute concentration or higher water molecules concentration to a region of higher solute concentration or lower water molecules concentration until equilibrium concentration is attained.

Based on the observation that when the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solution level rises, it means that water molecules have passed from the glucose solution through the semipermeable membrane into the unknown solution. Therefore, the solution has a higher solute concentration than the glucose solution.

3 0
3 years ago
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