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mr Goodwill [35]
3 years ago
7

A taxi company charges passengers $1.75 for a ride, no matter how long the ride is, and an additional $0.40 for each mile travel

ed. The rule mc014-1.jpg describes the relationship between the number of miles m and the total cost of the ride c. What is the charge for a 2.7-mile ride?
Mathematics
1 answer:
lions [1.4K]3 years ago
7 0
$2.4

 1.75+0.40x=2.7
-1.75            -1.75
-------------------------
            0.40x=0.95
            -------------
                  0.40
             X=2.375
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What is the volume of this rectangular prism?
Anton [14]

Answer:

15.625

Step-by-step explanation:

V=wxhxl=2.5x2.5x2.5=15.625

7 0
3 years ago
A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c
Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.06, \sigma = 1.1

0.06 = 2.575*\frac{1.1}{\sqrt{n}}

0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}

n = 2228.6

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0
3 years ago
Whats the most accurate estimation of 65 77
Gwar [14]
Addition: 70 + 80 = 150.  You round 65 up because the ones digit is greater than and the same with 77.
Multiplication: Round up since both ones digits are bigger than 5.  70 x 80= 5600.
5 0
3 years ago
The weight of a child in 1990 was 40 lb. By 2005, the child's weight
Maslowich

Answer:

225%

Step-by-step explanation:

1. Divide the new weight by the original weight.

90/40 = 2.25.

2. Multiply by 100 to get the percentage.

2.25 x 100 = 225%

5 0
3 years ago
The accompanying data contains the depth​ (in kilometers) and​ magnitude, measured using the Richter​ Scale, of all earthquakes
Sunny_sXe [5.5K]

Answer:

Depth:

μ =20.2025 km

M = 15.625 km

Range = 47.15 km

σ ≈ 15.92 km

Q₁ = 5.7375 km

Q₃ =  34.6675 km

Magnitude:

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

Step-by-step explanation:

The given data are;

Depth {}                                 Magnitude

0.76 {}                                    0.84

4.93 {}                                    0.47

8.16 {}                                     0.35

33.58 {}                                  1.32

21.2 {}                                     1.61

35.03 {}                                  4.57

10.05 {}                                   5.52

47.91 {}                                    1.99

For the Depth, we have;

The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km

The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;

0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 , the median is therefore;

(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km

The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km

The Standard deviation of, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{N}}

Where;

x_i = The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 )

N = The total number of data point = 8

Substituting, (using Microsoft Excel) we get;

\sigma =\sqrt{\dfrac{\sum \left (x_i-20.2025  \right )^{2} }{8}} \approx 15.92 \ km

Q₁ = The first quartile = The (n + 1)/4th =  term arranged in increasing order

Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km

Q₃ = The first quartile = The 3×(n + 1)/4th =  term arranged in increasing order

Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km

For the magnitude, we have, using the same formulas and procedures as above;

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

4 0
3 years ago
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