a^2 + b^2 = c^2
Let c = hypotenuse = 2x
One of the legs = x. Let a or b = x.
I will let a = x. We can then say that b = 3.
3^2 + x^2 = (2x)^2
9 + x^2 = 4x^2
9 = 4x^2 - x^2
9 = 2x^2
9/2 = x^2
sqrt{9/2} = sqrt{x^2}
3/sqrt{2} = x
Rational denominator.
[3•sqrt{2}]/2 = x = a
Side 3 is given to be 3 feet. So, b = 3.
Hypotenuse = 2x
Hypotenuse = 2([3•sqrt{2}]/2)
Hypotenuse = 3•sqrt{2}
Understand?
The three sides are 3, [3•sqrt{2}]/2 and
3•sqrt{2}.
Answer:
B
Step-by-step explanation:
Cos is the adjacent side over the hypotenuse. The adjacent side to <E is side ED. The hypotenuse is side EF. ED/EF. They do not go right out and give you this choice, but you see that B says the same thing.
Answer:
ΔCTA ≅ ΔDRA
Step-by-step explanation:
Triangles CTA and DRA are congruent by ASA postulate. This is because:
- ∠A is the same for both triangles (they are opposite angles)
Then, correspondent angles and sides are congruent, for example, ∠3 ≅ ∠4