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allsm [11]
3 years ago
6

Write an equation to match each graph:

Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

Answer:

y = x^2 + 2x - 3

Step-by-step explanation:The roots are -3 and 1. To write a quadratic in factored form, you must work backwards. x = -3; x + 3 = 0. x = 1; x - 1 = 0. The factored form of the quadratics is y = (x + 3)(x - 1). To write it in standard form multiply. The equation is y = x^2 + 2x - 3.

babymother [125]3 years ago
4 0

Answer:

Oblique downward straight line expression:

y=-x(x\geq 1)

Straight line expression:

y=-x+2(x\geq 1)

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Which equation is the inverse of y = 9x2 – 4?
devlian [24]

<u>Answer:</u>-

The two inverses are,

y = \sqrt {\frac{x+4}{9}}

and,  y =  - \sqrt {\frac{x+4}{9}}

<u>Step-by-step calculation:-</u>

y = 9 \times x^{2} - 4

⇒x^{2} = \frac{y+4}{9}

⇒x = \mp \sqrt {\frac{y+4}{9}}

So, the two inverses are,

y = \sqrt {\frac{x+4}{9}}

and,  y =  - \sqrt {\frac{x+4}{9}}

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3 years ago
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6x - 4(x + 3)
6x -4x -12. Distribute
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melisa1 [442]

Answer:

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Step-by-step explanation:

Remember i^2=-1

You are given the fraction \dfrac{3+5i}{-2+3i}

First, multiply the numerator and the denominator by -2-3i:

\dfrac{3+5i}{-2+3i}=\dfrac{(3+5i)(-2-3i)}{(-2+3i)(-2-3i)}=\dfrac{(3+5i)(-2-3i)}{(-2)^2-(3i)^2}=\dfrac{(3+5i)(-2-3i)}{4-9i^2}=\dfrac{(3+5i)(-2-3i)}{4+9}

This gives you 13 in denominator, now multiply two complex numbers in numerator:

(3+5i)(-2-3i)=-6-9i-10i-15i^2=-6-19i+15=9-19i

Thus, the initial fraction is

\dfrac{9-19i}{13}=\dfrac{9}{13}-\dfrac{19}{13}i

4 0
3 years ago
The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for
MrRissso [65]
Part A: Let the September price be x, then
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3 years ago
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