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posledela
3 years ago
13

Identify the Type II error if the null hypothesis, H0, is: The capacity of Anna's car gas tank is 10 gallons. And, the alternati

ve hypothesis, Ha, is: Anna believes the capacity of her car's gas tank is not 10 gallons.
Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0

Answer:

20gallons

Step-by-step explanation:

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It’s 12 that’s the simple answer
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Please answer the question
DIA [1.3K]

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J

Step-by-step explanation:

If you were to plug in your variables, you would see that -6, and -7 is over 25 and the rest of your variables aren't. So, therefore your answer is J.

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3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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3 years ago
No link please……. Enter the value of b when the expression 30.4x + b is equivalent to 3.4 (6x-3.1)
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Answer:

61

Step-by-step explanation

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2 years ago
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A line connecting a vertex of a scalene triangle with the midpoint of the opposite side is the
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The line would be called the median. The definition of '<span>A line connecting a vertex of a scalene triangle with the midpoint of the opposite side' pertains to the median. There are three medians that connect the scalene triangle. </span>
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2 years ago
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