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goldfiish [28.3K]

3 years ago

9

For three consecutive numbers, the sum of the first number, twice the second and 7 less than the third is 133. What are the thre

e numbers?

1 answer:

babunello [35]3 years ago

8 0

Answer:

34, 35, 36

Step-by-step explanation:

1st number = x

2nd number = x+1

3rd number = x+2

So the equation would be:

x+2(x+1)+(x+2)-7=133

x+2x+2+x+2-7=133

4x-3=133

4x=136

x=34

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In graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded ad labeled B, and the area where f(x) and g

NNADVOKAT [17]

Answer:

The graph represents the system of inequalities y ≤ -3x + 2 and y ≤ -x + 2 ⇒ C

Step-by-step explanation:

From the given figure

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∴ The coefficient of x in each inequality is negative ⇒ (1)

∵ The two lines intersect the y-axis at the point (0, 2)

∴ The y-intercept of the two lines is (0, 2)

∵ The y-intercept is the numerical term in the equation

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→ Look at the answer and find which one has the 3 conditions above

∵ y ≤ -3x + 2 and y ≤ -x + 2

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5 0

2 years ago

Plz help pe with this guys, thank you.

Burka [1]

31.+ addition
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7 0

3 years ago

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Marysya12 [62]

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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The long division method is shown below.

$\frac{(x^3-7x-6)}{x-4}=(x^2+4x+9)+\frac{30}{x-4}$

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