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goldfiish [28.3K]
4 years ago
9

For three consecutive numbers, the sum of the first number, twice the second and 7 less than the third is 133. What are the thre

e numbers?
Mathematics
1 answer:
babunello [35]4 years ago
8 0

Answer:

34, 35, 36

Step-by-step explanation:

1st number = x

2nd number = x+1

3rd number = x+2

So the equation would be:

x+2(x+1)+(x+2)-7=133

x+2x+2+x+2-7=133

4x-3=133

4x=136

x=34

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What is the maximum angle of a pendulum?

Paul Appell pointed out a physical interpretation of the imaginary period: if θ0 is the maximum angle of one pendulum and 180° − θ0 is the maximum angle of another, then the real period of each is the magnitude of the imaginary period of the other.

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The radius of a circle is 2.5 cm. Find the circumference
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Directions: Solve the following by multiplying by the inverse of the fractional coefficient. 1. \frac{2}{5} t = 20 2. \frac{7}{8
coldgirl [10]

The answer of the following options are as 50, 64, 36, 40, 100, 9, 12, 12 100, 27, 150 42, 50 72, 28.3.

<h3>How to interpret the fraction?</h3>

Suppose the fraction is proper (the numerator is smaller than the denominator).

Let it be

\dfrac{a}{b}

Then, we can interpret it as:

a parts out of b parts of a thing.

1. \dfrac{2}{5} t = 20\\\\t = 20 \times \dfrac{5}{2}\\\\t= 50

2. \frac{7}{8} p = 56\\\\p = 56 \times \frac{8}{7} \\\\ p= 64

3. \frac{5}{6} x = 30 \\\\x = 30 \times \frac{6}{5}  = 36

4. \frac{1}{2} x = 20\\\\x = 20 \times 2 = 40

5. \frac{3}{5} s = 60\\\\s = 60 \times \frac{5}{3} = 100

6. \frac{1}{3} t = 3 \\\\t = 3\times 3 = 9

7. \frac{3}{4} x = 9\\\\x = 12

8. \frac{11}{12} x = 11\\\\x = 11 \times 12/11 = 12

9. \frac{8}{10} t = 80\\\\t = 80 \times 10/8 = 100

10. \frac{p}{3} = 9 \\\\p = 9 \times 3 = 27

11. \frac{n}{5} = 30\\\\n = 30 \times 5 = 150

12. \frac{6a}{7} = 36 \\\\a = 36 \times 7/6 = 42

13. \frac{1}{2} t + 3 = 28\\\\t = (28 - 3)2 = 50

14. \frac{1}{6} r = 12\\\\r = 12\times 6 = 72

15. \frac{11}{12} b = 32\\ \\b = 32 \times 11/12 = 29.33

Learn more about fraction here:

brainly.com/question/27010538

#SPJ1

3 0
2 years ago
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