Answer:
Step-by-step explanation:
Given
Area of a floor = 2040ft²
If Its length is 36ft. longer than its width, then L = W+36
Area = LW
L is the length
W is the width
A < W(W+36)
2040 < W²+36W
0<W²+36W-2040
W²+36W-2040 >0
W = -36±√36²-4(-2040)/2
W = -36±√1296+8160)/2
W = -36±√9456/2
W = -36±97.25/2
W = -36+97.25/2
W = 61.24/2
W > 30.62ft
Since L = W+36
L > 30.62+36
L > 66.62ft
The width of the floor is 30.62ft
The length is 66.62ft
The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft
The possible dimension of the floor is 31ft by 67 ft
The possible areas is 31*67 = 2077ft²
It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²
Let's say make the shapes, some variable name
say
⛁ ⚪ ◽ ▯
a b c d
so.. if take those are the shapes provided
then we can take a look at the first set and we can say that
2a + b + c = 20
a + 4d + b = 19
a + c = 9
3c + d + a = 19
thus
and surely you can find the other two
Answer:
Step-by-step explanation:
It might be A or D I’m not for sure which one it is.
Answer:
Sue traveled 1,685 miles.
Step-by-step explanation:
337 x 5
(300 x 5) + (30 x 5) + (7 x 5)
1,500 + 150 + 35
1,650 +35
1,685