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3 years ago

Find the sum of the first 6 terms of geometric series 2-10+50+.....

Mathematics

1 answer:

barxatty [35]3 years ago

8 0

<h3>Answer: -5208</h3>

============================================

Work Shown:

term1 = 2

term2 = -10

term3 = 50

term4 = -250

term5 = 1250

term6 = -6250

Each new term is found by multiplying the previous term by -5

Add up the terms

2 + (-10) + 50 + (-250) + 1250 + (-6250) = -5208

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A shortcut is to use a = 2, r = -5 and n = 6 in the formula below

Sn = a*(1-r^n)/(1-r)

S6 = 2*(1-(-5)^6)/(1-(-5))

S6 = 2*(1-15625)/(1+5)

S6 = 2*(-15624)/6

S6 = -31248/6

S6 = -5208

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3 years ago

are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of

galben [10]

Answer:

The best estimate of the area of the larger figure is $693\ cm^{2}$

Step-by-step explanation:

step 1

<em>Find the scale factor</em>

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

$z=\frac{x}{y}$

we have

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substitute

$z=\frac{12}{9}=\frac{4}{3}$ -----> the scale factor

step 2

<em>Find the area of the larger figure</em>

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

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y-----> the area of the smaller figure

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we have

$z=\frac{4}{3}$

$y=390\ cm^{2}$

substitute and solve for x

$(\frac{4}{3})^{2}=\frac{x}{390}$

$(\frac{16}{9})=\frac{x}{390}$

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Answer:

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Answer:

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2 years ago

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