<h3>
<u>Required</u><u> Answer</u><u>:</u><u>-</u></h3>
Here the height and length are the sides of the rectangular wall and we have to find the area.
Area of rectangle is given by:

where l is the length and b is the breadth/width according to the question. Plugging the given values:


<h3>
<u>Hence:</u><u>-</u></h3>
The area of the wall is <u>1</u><u>0</u><u>5</u><u>6</u><u>0</u><u> </u><u>inch²</u>
Answer:
Five touchdowns were made in the game
Step-by-step explanation:
Here, we want to know the number of touchdowns made during the game.
We proceed as follows;
Let the number of touch downs be x
So the total points earned through touchdowns is 6 * x = 6x
The number of scores is 10 times
Let the number of extra kick be y which means that the number of conversions will be (y-1)
So the total number of score times will be ;
x + y + y-1 = 10
x + 2y = 11 •••••••••(i)
Now let’s work with points
Touch down points = 6 * x = 6x
Points from extra kick = 1 * y = y
Points from 2-point conversions = 2(y-1) = 2y - 2
So;
6x + y + 2y -2 = 37
6x + 3y = 37 + 2
6x + 3y = 39
divide through by 3
2x + y = 13 •••••••(ii)
So now solve simultaneously
From ii, y = 13 - 2x
Put this into i
x + 2(13-2x) = 11
x + 26 - 4x = 11
x -4x = 11-26
-3x = -15
x = -15/-3
x = 5
There are five touchdowns in the game
<h2>
Horizontal distance when projectile strikes water surface is 170 .02 feet</h2>
Step-by-step explanation:
The height is given by

We need to find when it strikes the water surface,
At water surface h = 0 feet
Substituting

Solving this quadratic equation to get x.
-32x² + 2500x + 500000 = 0
32x² - 2500x - 500000 = 0
x = 170 .02 feet or x = -91.90 feet
Negative x is not possible
Horizontal distance when projectile strikes water surface = 170 .02 feet
Answer:
C
Step-by-step explanation: