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shutvik [7]
3 years ago
15

Why is 1 always a gcf of two numbers

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0
But it's not one doesn't always have to be the gcf
You might be interested in
Find the equation of the axis of symmetry of the following parabola algebraically.<br> y=2x^2+16.
Inessa05 [86]

Answer:

x = 0

axis of symmbery = -b/2a or x vertex on quadratic equation

0/4=0

x=0

Step-by-step explanation:

3 0
2 years ago
List from least to greatest
balandron [24]
2/5 | 52% | 0.57 is the answer
6 0
2 years ago
Evaluate each of the expressions in the list for y = 5. Drag and drop the correct number into each box to
malfutka [58]

Answer:

Step-by-step explanation:

To get the value of the expressions in list A and list B we will substitute y = 5 in each expression.                      

            List A                                        List B

1). 6 + 6y = 6 + 6(5) = 36              6y - 6 = 6(5) - 6 = 24

2). 6(y - 1) = 6(5 - 1) = 24               6(y + 1) = 6(5 + 1) = 36

3). 6y + 1 = 6(5) + 1 = 31                 1 + 6y = 1 + 6(5) = 31

Therefore, (6 + 6y) is equivalent to 6(y + 1)

6(y - 1) is equivalent to (6y - 6)

(6y + 1) is equivalent to (1 + 6y)

4 0
2 years ago
Add 1} + (-5) using the number line.
gizmo_the_mogwai [7]

Answer:

1/2

Step-by-step explanation:

1 1/3+(-5/6)

1 1/3=4/3

4/3+(-5/6)

4/3-5/6

8/6-5/6

3/6

simplify

1/2

6 0
3 years ago
(-9) + (-4) =
Gwar [14]

\\ \bull\sf\longmapsto -9+(-4)=-9-4=-13

\\ \bull\sf\longmapsto +3-(-5)=3+5=8

\\ \bull\sf\longmapsto 2\times 2=4

\\ \bull\sf\longmapsto 36+4=40

\\ \bull\sf\longmapsto 5\times 7=35

\\ \bull\sf\longmapsto 8(9)=72

\\ \bull\sf\longmapsto -4+(-2)=-4-2=-6

\\ \bull\sf\longmapsto 3-(-6)=3+6=9

\\ \bull\sf\longmapsto -6(-3)=18

\\ \bull\sf\longmapsto -4+(-4)=-4-4=-8

\\ \bull\sf\longmapsto 5(7)=35

\\ \bull\sf\longmapsto 4-(-5)=4+5=9

\\ \bull\sf\longmapsto 4-3=1

\\ \bull\sf\longmapsto 10+5=15

\\ \bull\sf\longmapsto 3(8)=24

7 0
2 years ago
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