these marbles are placed in a bag and two of them are randomly drawn. yellow=2 pink=3 blue=5 what is the probability of drawing
2 yellow marbles if the first one is not placed back into the bag before the second one. Give your answer as a rational number, reduced to simplest terms.
The probability of drawing the first yellow ball will be= 2/10
Since the ball is not replaced, that means there will be 9 balls left and 1 yellow ball left. Therefore, the probability of drawing the second yellow ball will be = 1/9
The probability of drawing two yellow balls if they're not replaced will now be:
