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3 years ago

12

A hairdresser gives between 6 and 20 haircuts in a day. She works six days per week. What is a reasonable estimate of the number

of haircuts she gives in a week?

1 answer:

mr Goodwill [35]3 years ago

5 0

20+6=26/2=13 haircuts per day
13*6=78 haircuts

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. The simplest form o

sleet_krkn [62]

Answer:

x

Step-by-step explanation:

-2x²(x – 5) + x(2x² – 10x) + x

The simplest for of the above equation can be obtained as follow:

-2x²(x – 5) + x(2x² – 10x) + x

Rearrange

x(2x² – 10x) – 2x²(x – 5) + x

Factorise

x.2x(x – 5) – 2x²(x – 5) + x

2x²(x – 5) – 2x²(x – 5) + x

Carry out the minus (–) operation

=> x

Therefore, the simplest form of expressing -2x2(x – 5) + x(2x2 – 10x) + x is x.

6 0

3 years ago

2. A package of ground beef costs $6.98. The price per pound is $3.86. How many pounds of ground beef are in the package? Round

Cerrena [4.2K]

1.81 pounds
you divide 6.98/3.86

8 0

2 years ago

HELP PLEASE I really don’t understand it

valina [46]

Answer:

i think its b

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Please help me with these. These are so hard.<br><br>

LuckyWell [14K]

$\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}$

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0

3 years ago

A certain chain of ice cream stores sells 28 different flavors, and a customer can order a single-, double- , or triple-scoop co

astra-53 [7]

<span>Think about the cones with only 1 scoop of ice cream. Isn't it clear that there are 28 of those?
Now think about the two scoop cones. You have 28 choices for the first scoop and 28 choices for the second scoop.
So the number of possibilities is 28(28).
Now think of the 3 scoop cones.
You have 28 choices for the first scoop, 28 choices for the second scoop, and 28 choices for the third scoop or 28(28)(28) possibilities.
Add them all together and you have the total.

So it will be like this:
</span><span>28^3+28^2+28
</span>
I hope my answer helped you.

6 0

2 years ago