Answer:
QSR = 68º
Step-by-step explanation:
TSQ + QSR = TSR
15x + (10x - 2) = 173
Combine like terms
25x = 175
Divide both sides by 25
x = 7
QSR = 10x - 2
QSR = 10(7) - 2
QSR = 68º
We can see on this graph that the triangle has legs of x and 6 with a hypotenuse of 10 and we can use Pythagoreans theorem to find the unknown side.
Pythagoreans theorem: a^2+b^2=c^2, where a and b are the legs of the triangle and c, is the hypotenuse
x^2+6^2=10^2 Plugin a=x, b=6, and c=10. Now let us solve for x
x^2+36=100 Square each individual term
x^2+=100+36 Subtract 36 from both sides
x^2=64 Combine like terms
sqrt(2)=sqrt(64) Take the square root of both sides
x = 8 Simplify the square root
So our answer is x = 8
The ladder touches the 8 feet mark on the wall.
<span>After 1 hour, the diving bell was -1/2 mile relative to sea level.
Since the rate of decent is constant, we can use two ratios to represent the depth at 2 different times. To make things easier to write, I'll use decimals to represent time and depth.
-.75 / 1.5 = x / 1
Now solve for x
-0.5 = x
So after 1 hour, the diving bell was -1/2 mile relative to sea level.</span>
2040 = n/2(20+(n-1)4)
4080 = n(20+4n-4)
4080= 20n +4n^2 -4n
1020 = 4n + n^2
n^2 +4n -1020 =0
use common formula (can't write out so just look at answers. sorry)
which gives answers of n=-34 and n=30. since n can only be positive, n=30 so there are 30 rows. I liked that challenge
