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devlian [24]
3 years ago
5

the density of a certain material is such that weighs 6900 grams for every 4.5 quarts of volume express this density in pounds p

ounds per cubic foot
Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

d=101.4\ \text{pounds}/\text{feet}^3

Step-by-step explanation:

Given that,

Mass of material, m = 6900 grams

Volume of the material, V = 4.5 quarts

We need to find the density in pounds per cubic foot

We know that,

1 pound = 453.59 grams

⇒ 6900 grams = 15.21 pounds

Also, 1 cubic foot = 29.92 quarts

4.5 quart = 0.15 feet³

Density = mass/volume

Or

d=\dfrac{15.21\ \text{pounds}}{0.15\ \text{feet}^3}\\\\d=101.4\ \text{pounds}/\text{feet}^3

Hence, the density of the material is 101.4\ \text{pounds}/\text{feet}^3

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Answer:

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
What is the sale price for your purchase if you have a 20% off coupon and you buy a shirt for $19.99 and pants for $10.
Andrew [12]
Answer: I believe it is $23.99

Explanation:
19.99+10= 29.99
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I hope this helped!
4 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

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3 years ago
Which country was the first to industrialize on the continent of Europe
maxonik [38]

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3 years ago
HELP WITH FINANCIAL LIT--WILL MARK BRANLIEST--
Dominik [7]
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Subprime lending is lending money to people with a low credit score that was not really fit for the credit. This means the risk of getting the money back would be higher than prime lending. Since the risk of losing the money is higher, the interest should be higher than prime lending.

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Total liability= $1,500+ $7,500= $9,000Net worth= $5,500- $9,000= - $3,500
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4 years ago
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