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jok3333 [9.3K]
4 years ago
8

Reynolds Manufacturers Inc. has estimated total factory overhead costs of $116,000 and expected direct labor hours of 11,600 for

the current fiscal year. If job number 117 incurs 1,700 direct labor hours, Work in Process will be debited and Factory Overhead will be credited for
Business
1 answer:
Damm [24]4 years ago
5 0

Answer:

Overhead= $17,000

Explanation:

Giving the following information:

estimated total factory overhead costs of $116,000

expected direct labor hours of 11,600

Job number 117 incurs 1,700 direct labor hours

First, we need to calculate the predetermined manufacturing overhead rate:

Predetermined manufacturing overhead rate= total estimated overhead costs for the period/ total amount of allocation base

Predetermined manufacturing overhead rate= 116,000/11,600

Predetermined manufacturing overhead rate= $10 per direct labor hour

Now, we can determine the amount of allocated overhead:

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

Allocated MOH= 10*1,700= 17,000

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3 years ago
If your company does not have a manual that describes all the major product warranties, you should:
bagirrra123 [75]

Answer:

C. Decide on a general, neutral comment you can make if customers ask you about a warranty

Explanation:

The comment might be that each product contain the warranty within the box.

3 0
4 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
4 years ago
Pes
lakkis [162]

Answer:

ushsj

Explanation:

bshshshhdshshshhshdbshjdjdkdjddjjdndndndnfnfkdk

8 0
4 years ago
An airline is considering a project of replacement and upgrading of machinery that would improve efficiency. The new machinery c
Nikolay [14]

Answer:

$172.25

Explanation:

initial outlay for the project = -$350

cash flow years 1-5 = [($300 - $135 - $70) x (1 - 36%)] + $70 (depreciation expense) = $60.80 + $70 = $130.80

using an excel spreadsheet and the NPV function, we can calculate the project's NPV with an 8% discount rate:

=NPV(8%,130.80,130.80,130.80,130.80,130.80) - $350 = $522.25 - $350 = $172.25

we can also do it manually:

NPV = -$350 + $130.80/1.08 + $130.80/1.08² + $130.80/1.08³ + $130.80/1.08⁴ + $130.80/1.08⁵ = $172.25

6 0
4 years ago
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