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4 years ago

Express 24.357 in unit form

Mathematics

1 answer:

Lorico [155]4 years ago

6 0

2 tens, 4 ones, 3 tenths, 5 hundredths, 7 thousandths

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Mr. Chang’s class has 28 students, StartFraction 4 Over 7 EndFraction of whom are girls. Which equation shows how to determine t

Olegator [25]

Answer:

Okay, so we know a number of students and the amount of girls as a bracket. So what we have to do now is multiply them with each other.

28 *4/7 = 16

So there are 16 girls in Mr. Chang´s class.

You can also determine the boys by - the students with the girls:

28-16=12 boys

Have a nice day :D

Step-by-step explanation:

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3 years ago

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Ln x=-3<br> How to solve

Natasha2012 [34]

Answer: x=0.050

Step-by-step explanation:

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3 years ago

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Please help on this

Gennadij [26K]

Answer:

5.025m

Step-by-step explanation:

The clothesline also creates an upside-down triangle with two sides being 5m, 0.5m, and the hypotenuse being the clothesline.

We can use the pythagorean theorem to find the length of the clothesline.

5 squared +.5 squared= the length of the clothesline squared

25+.25= the square root of 25.25

= 5.025

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2 years ago

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Could I get some help with this question? Thanks

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Answer:

I am unable to see the picture if you type it i can possibly help

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3 years ago

A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: $\frac{X-\mu}{\sigma}$

Therefore

$\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}$

$\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}$

$-1.5\leq z\leq 2.5$

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

$P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270$

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

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4 years ago